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0.5x^2-7=74
We move all terms to the left:
0.5x^2-7-(74)=0
We add all the numbers together, and all the variables
0.5x^2-81=0
a = 0.5; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·0.5·(-81)
Δ = 162
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{162}=\sqrt{81*2}=\sqrt{81}*\sqrt{2}=9\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-9\sqrt{2}}{2*0.5}=\frac{0-9\sqrt{2}}{1} =-\frac{9\sqrt{2}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+9\sqrt{2}}{2*0.5}=\frac{0+9\sqrt{2}}{1} =\frac{9\sqrt{2}}{1} $
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